Problema Solution
from a group of ten boys and twelve girls, a committee of four students is chosen at random. What is the probability that:
a. all four members of the committee will be girls?
b. all four member of the committee will be boys?
c. there will be a least one girl on the committee?
Answer provided by our tutors
a.
P(all are girls) = C(12, 4)/C(22, 4)
C(12, 4) = 12!/(4!(12 - 4)!) = 9*10*11*12/4! = 495
C(22, 4) = 22!/(4!(22 - 4)!) = 19*20*21*22/4! = 7315
P(all are girls) = 495/7315
P(all are girls) = 0.06767
b.
P(all are boys) = C(10, 4)/C(22, 4)
C(10, 4) = 10!/4!(10 - 4)!)
C(10, 4) = 7*8*9*10/4!
C(10, 4) = 210
P(all are boys) = 210/7315
P(all are boys) = 0.02871
c.
P(there is at leas 1 girl) = 1 - P(there are no girls) = 1 - P(all are boys)
P(there is at leas 1 girl) = 1 - 0.02871
P(there is at leas 1 girl) = = 0.97129