Problema Solution
High concentrations of carbon monoxide CO can cause coma and possible death. The time required for a person to reach a COHb level capable of causing a coma can be approximated by the quadratic model T=.0002x^2−.316x+127.9, where T is the exposure time in hours necessary to reach this level and 500≤x≤800 is the amount of carbon monoxide present in the air in parts per million (ppm).
a) What is the exposure time when x=570570?
b) Estimate the concentration of CO necessary to produce a coma in 88 hr.
What is the exposure time when x=570570?
Answer provided by our tutors
a) Plug the value for x = 570 into T=.0002x^2−.316x+127.9:
T=.0002*570^2−.316*570+127.9
T = 12.76 hours
The exposure time when x=570 is 12.76 hours.
b) T = 88 hr and we need to find x
0.0002x^2−0.316x+127.9 = 88
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click here to see the equation solved for x
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x1 = 1441.61 ppm
x2 = 138.39 ppm