Problema Solution
how many gallons of 40% antifreeze should be mixed with 10 gallons of 80%antifreeze to obtain a 65% antifreeze mixture
Answer provided by our tutors
Let
x = gal of 40% antifreeze
0.40x + 0.80*10 = 0.65(x + 10)
........
click here to see the equation solved for x
........
x = 6 gal
6 gallons of 405 antifreeze should be used for the mix.