Problema Solution
How many gallons of a 25% antifreeze solution and a 10% antifreeze solution must be mixed to obtain 15 gallons of a 22% antifreeze solution
Answer provided by our tutors
Let
x = gallons of a 25% antifreeze solution
y = gallons of a 10% antifreeze solution
Now, we can writ the following system of equations:
x + y = 15
0.25x + 0.10y = 0.22*15
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Click here to see the step by step solution for the system of equations
........
x = 12 gal
y = 3 gal
12 gallons for a 25% antifreeze solution and 3 gallons of a 10% antifreeze solution must be mixed.