Problema Solution
How much tin and how much lead must be added to 700 pounds of alloy containing 50 percent tin and 25 percent lead to make an alloy which is 60 percent tin and 20 percent lead?
Answer provided by our tutors
Let
x = lbs of tin (100% tin and 0% lead)
y = lbs of lead (0% tin and 100% lead)
We have the following system of equations:
0.50*700 + 1.00*x + 0*y = 0.60(700 + x + y)
0.25*700 + 0*x + 1.0*y = 0.20(700 + x + y)
........
click here to see the system of equations solved for x and y
........
x = 175 lbs tin
y = 0 lbs lead
175 pounds of tin and 0 pounds of lead should be added to the alloy.