Problema Solution
if a coin is thrown with a starting velocity of 0 m/s down a dry well and hits bottom is 1.2 seconds, what is the depth of the well?
Answer provided by our tutors
The depth of the well equals the distance traveled by the ball:
s = v1t + (1/2)(gt^2)
v1 = 0 m/s
t = 1.2 s
g = 9.8 m/s^2
s = (1/2)(9.8*1.2^2)
s = 7.056 m
The depth of the well is 7.056 meters.