Problema Solution
If a single die is rolled eight times, what is the probability it lands on 6 on the fourth, fifth, sixth, and seventh seventh rolls, but not on any of the other rolls?
Answer provided by our tutors
The event when the die lands on 6 on the fourth, fifth, sixth, and seventh seventh rolls but not on any of the other rolls can be represented by:
x1, x2, x3, 6, 6, 6, 6, x4
where x1, x2, x3 anb x4 are numbers from 1 to 5
The total number of different rolls that can occur is:
6^8
The number of the events where the dice lands on 6 on the fourth, fifth, sixth, and seventh seventh rolls, but not on any of the other rolls is:
5*5*5*1*1*1*1*5 = 5^4
P(x1, x2, x3, 6, 6, 6, 6, x4) = 5^4/6^8
P(x1, x2, x3, 6, 6, 6, 6, x4) = 0.00037
The probability is 0.00037.