Problema Solution
If a single die is rolled five times, what is the probability it lands on 6 on the second, third and fourth and nothing rolls, but not on any of the other rolls?
Answer provided by our tutors
The event when the die lands on 6 on the second, third and fourth rolls but not on any of the other rolls can be represented by:
x1, x2, 6, 6, 6
where x1, x2 are numbers from 1 to 5
The total number of different rolls that can occur is:
6^5
The number of the events where the dice lands on 6 on the second, third and fourth rolls but not on any of the other rolls is:
5*5*1*1*1 = 5^2
P(x1, x2, 6, 6, 6) = 5^2/6^5
P(x1, x2, 6, 6, 6) = 0.0032
The probability is 0.0032.