Problema Solution
If an object is projected upward with an initial velocity of 125 ft per sec, its height h after t seconds is h=-16t^2+125t. What is the height of the object after 4 seconds?
Answer provided by our tutors
h(t) = -16t^2+125t
We need to find h(t) when t = 4 s:
h(4) = -16*4^2+125*4
h(4) = 244 ft
The height of the object after 4 seconds is 244 feet.