Problema Solution
If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?
Answer provided by our tutors
x = 3 + bi and |x|^2 = 13
3^2 + b^2 = 13
b^2 = 13 - 9
b^2 = 4
There are two possible values for b: 2 and -2.
If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?
x = 3 + bi and |x|^2 = 13
3^2 + b^2 = 13
b^2 = 13 - 9
b^2 = 4
There are two possible values for b: 2 and -2.