Problema Solution

If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?

Answer provided by our tutors

x = 3 + bi and |x|^2 = 13

3^2 + b^2 = 13

b^2 = 13 - 9

b^2 = 4

There are two possible values for b: 2 and -2.