Problema Solution
If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
Answer provided by our tutors
The standard form equation of a circle with center at (h, k) and radius 'r' (r >=0) is:
(x - h)^2 + (y - k)^2 = r^2
First we will find (h, k) as the middle point of the segment with end points (−6, 6) and (6, −2):
h = (1/2)(6 + (-6))
h = 0
k = (1/2)(- 2 + 6)
k = 2
The center is (0, 2).
Next, we will find the radius:
r^2 = (0 - (-6))^2 + (2 - 6)^2
r^2 = 36 + 16
r^2 = 52
The standard for of equation is:
(x - 0)^2 + (y - 2)^2 = 52
x^2 + (y - 2)^2 = 52
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