Problema Solution
If the length is 7 more than 4 times the width of a rectangle and the perimeter is 74mm, what are the dimensions
Answer provided by our tutors
Let
L = the length of the rectangle
W = the width of the rectangle
P = 74 mm the perimeter of the rectangle
L = 7 + 4W
2L + 2W = 74 (since P = 2L + 2W)
We have the following system of equations:
L = 7 + 4W
2L + 2W = 74
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L = 31 mm
W = 6 mm
The dimensions of the rectangle are: the length is 31 mm while the width is 6 mm.