Problema Solution
In 2004, there were 8,569 Starbucks stores. In 2006, there were 12,440 Starbucks stores. If Starbucks continues to increase exponentially at the same rate find the doubling time
Answer provided by our tutors
If a quantity starts at size P0 and grows by r% (written as a decimal, r) every time period, then the quantity after n time periods can be determined using either of these relations:
Pn = Po*(1+r)^n
We will correspond n = 0 with the year of 2004, as that is the year for the first piece of data we have. That will make P0 = 8,569 Starbucks stores. In this problem, we are not given the growth rate, but instead are given that P2 = 12,440 Starbucks stores.
When n = 2, the explicit equation looks like:
P2 = P0*(1+r)^2
We know the value for P0 = 8,569, so we can put that into the equation:
P2 = 8569*(1+r)^2
We also know that P2 = 12,440, so substituting that in, we get
12,440 = 8569*(1+r)^2
8569*(1+r)^2 = 12,440
........
click here to see the equation solved for r
........
r = 0.205 or 20.5%
Now the equation of the growth is:
Pn = P0*(1+0.205)^n
We need to find n such that Pn = 2P0 that is:
2P0 = P0*(1+0.205)^n
P0*(1+0.205)^n = 2P0 divide both sides by P0
1.205^n = 2
........
click here to see the equation solved for n
........
n = 3.72 years
The doubling time is 3.72 years.