In a right triangle the leg opposite to the acute angle of 30° is 7 in. Find the hypotenuse and other leg.
Let 'b' represent the other leg and 'c' the hypotenuse.
a = 7
cot 30 = b/a
cot 30 = b/7
b = 7*cot30
b = 7*√3
b = 12.12 in
c^2 = a^2 + b^2
c^2 = 7^2 + (7*√3)^2
c^2 = 196
c = 14 in
The hypotenuse is 14 in while the other leg is 12.12 in.