Problema Solution
In ∆ABC, AB = 4.12, BC = 4, AC = 5. What is m C?
Answer provided by our tutors
We will use The Law of Cosines for finding the angle <C:
c^2 = a^2 + b^2 - 2ab cos(<C)
<C means the same as m C
cos(<C) = (a^2 + b^2 - c^2)/(2ab)
a = 4, b = 5, c = 4.12
cos(<C) = (4^2 + 5^2 - 4.12^2)/(2*4*5)
cos(<C) = 0.60064
<C = arccos(0.60064)
<C = 53 degrees approximately that is
m C = 53 degrees