Problema Solution
in his report for the day, the cashier of the snack bar turned a number of coins amounting to $6.25 consisting of nickles and dimes. if there were three times as many nickles as there were dimes, how many dimes were there?
Answer provided by our tutors
1 nickel = 5 cents
1 dime = 10 cents
$6.25 = 6125 cents
Let
n = the number of nickels, n>=0, n is integer
d = the number of dimes, d>=0, d is integer
5n + 10d = 625
n = 3d
........
click here to see the system of equations solved for n and d
........
n = 75 nickles
d = 25 dimes
There were 25 dimes.