Problema Solution
In isosceles ∆DEK with base
DK
,
EF
is the angle bisector of ∠E, m∠DEF = 43°, and DK = 16cm. Find: KF, m∠DEK, m∠EFD.
Answer provided by our tutors
Make a drawing and it will be easier to solve.
m∠DEK = 2*m∠DEF
m∠DEK = 2*43°
m∠DEK = 84°
KF = = DK/2
KF = 16/2
KF = 8 cm
m∠EFD = 90°