Problema Solution
John has 68 red marbles in one bowl 1 and 25 blue marbles in bowl 2. If John needed to choose five red marbles from bowl 1 and one blue marble from bowl 2, how many different possible combinations of five red and one blue marble can be chosen?
Answer provided by our tutors
C(68, 5) * C(25, 1) =
=(68!/(5!(68 - 5)!))*(25!/1!(25 - 1)!) =
= (64*65*66*67*68/120) * 25 =
= 260,603,200
There are 260,603,200 possible combinations of five red and one blue marble.