Problema Solution
Kacey drove from Chicago to Milwaukee, a distance of 92 miles. The return trip was made at an average speed that was 10 mph slower. If the total time for the trip was 3 hours, find the average speed on each part of the trip
Answer provided by our tutors
Let
d = 92 mi the distance in one direction
v = the average speed on the way to Milwaukee
v - 10 = the average speed on the way back to Chicago
t = 3 hours the total time
Since speed = distance/time follows time = distance/speed as we have:
v/d + (v - 10)/d = t
v/92 + (v - 10)/92 = 3
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click here to see the equation solved for v
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v = 143 mph
v - 10 = 143 - 10 = 133 mph
The average speed to Milwaukee was 143 mph, while the average speed on the way back to Chicago was 133 mph.