Problema Solution
Kristine has $26.40. if there are thrice as many 25 cent coin as 5 cent coin and twice as many $1.00 coin as 25 cent coin and 5 cent coin combined, how many coins of each type does she have?
Answer provided by our tutors
We will assume that Kristine has $1, 25 cent and 5 cent coins only.
Let
x = the number of $1 coins
y = the number of 25 cent coins
z = the number of 5 cent coins
y = 3z
x = 2(y + z)
100x + 25y + 5z = 2640 (since $1 = 100 cents, $26.40 = 1640 cents)
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click here to see the system of equations solved for x, y and z
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x = 24 coins of $1
y = 9 coins of 25 cents
z = 3 coins of 5 cents
Kristine has 24 coins of $1, 9 coins of 25 cents and 3 coins of 5 cents.