Problema Solution

Let f(x)= x2-3x and g(x)= 6+x

Find (fg)(1)

Answer provided by our tutors

Since (fg)(x) = f(x)*g(x) we have:

(fg)(1) = f(1)*g(1) = (1^2 - 3*1)*(6 + 1) = (-2)*7 = -14

(fg)(1) = -14