Problema Solution
Let f(x)= x2-3x and g(x)= 6+x
Find (fg)(1)
Answer provided by our tutors
Since (fg)(x) = f(x)*g(x) we have:
(fg)(1) = f(1)*g(1) = (1^2 - 3*1)*(6 + 1) = (-2)*7 = -14
(fg)(1) = -14
Let f(x)= x2-3x and g(x)= 6+x
Find (fg)(1)
Since (fg)(x) = f(x)*g(x) we have:
(fg)(1) = f(1)*g(1) = (1^2 - 3*1)*(6 + 1) = (-2)*7 = -14
(fg)(1) = -14