Problema Solution
Mary is 3 times as old as bhawna and the sum of their ages 5 years from now will be twice as mary's present age. How old are they now?
Answer provided by our tutors
Let
m = Mary's present age
b = Bhawna's present age
Mary is 3 times as old as Bhawna:
m = 3b
The sum of their ages 5 years from now will be twice as Mary's present age:
m + 5 + b + 5 = 2m
m + b + 10 = 2m
We have the following system of equations:
m = 3b
m + b + 10 = 2m
........
click here to see the system of equations solved for m and b
........
m = 15 years
b = 5 years
Mary is 15 years old now.
Bhawna is 5 years old now.