Problema Solution

Mason has 288 pennies, 240 dimes and 180 nickles. He wants to place the coins in stacks so that each stack has the same number of coins, and each stack contains only one denomination of coin. What is the largest number of coins that he can place in each stack?

Answer provided by our tutors

We need to find the Greatest Common Factor for 288, 240, 180:

GCF(288, 240, 180) = 12

The largest number of coins that Mason can place in each stack is 12.