Problema Solution
Mike can run the mile in 6 minutes and Dan can sun the mile in 9 minutes. If Mike gives Dan a head start of 1 minute, how far from the start will Mike pass Dan? How long does it take?
Answer provided by our tutors
v1 = 1/6 miles per min is Mike's average rate
v2 = 1/9 miles per minute is Dan's average rate
t = the time of Mike
t + 1 = time of Dam
Since the both run the same distance and distance = speed*time we have:
v1t = v2(t + 1)
(1/6)t = (1/9)(t + 1)
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click here to see the equation solved for t
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t = 2 min
2*(1/6) = 1/3 mi = 0.33 mi
Mike will pass Dan in 2 minutes, 0.33 miles from the start.