Problema Solution
Ming has 15 quarters,30 dimes, and 48 nickels. He want to group his money so that each group has the same number of each coin. What is the greatest number of groups he can make? How many of each coin will be in each group? How much money will each group be worth?
Answer provided by our tutors
Since the greatest common factor for 15, 30 and 48 is 3 ( click here to see the calulcation: GCF(15, 30, 48) = 3 ) the greatest number of groups that he can make is 3.
There will be 15/3 = 5 quarters, 30/3 = 10 dimes, 48/3 = 16 nickles.
Each group will be worth: 5*0.25 + 10*0.10 + 16*0.05 = $3.05.