Problema Solution
One positive integer is 4 less than twice another. The sum of their squares is 100. Find the integers.
Answer provided by our tutors
Let 'x' and 'y' represent the positive integers, x >0, y>0.
y = 2x - 4
The sum of their squares is 100 means:
x^2 + y^2 = 100
Plug y = 2x - 4 into the last equation:
x^2 + (2x - 4)^2 = 100
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click here to see the equation solved for x
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x = 6
We need to ignore the negative solution -2.8 since x can only be positive.
y = 2*6 - 4
y = 12 - 4
y = 8
Indeed 6^2 + 8^2 = 36 + 64 = 100.
The two positive integers are 6 and 8.