Problema Solution
One wall of the bathroom is covered with tile arranged in rows.Each tile is a square with sides measuring 8 inches.The wall is 6 feet wide.How many tiles are in each row? What is the total area covered by one row of tiles?
Answer provided by our tutors
The area of one tile is:
8*8 = 64 in^2
The area of the wall is:
(6*12)*(6*12) = 5,184 in^2 (since 1 ft = 6 in)
The number of tiles needed is:
5,184 : 64 = 81 tiles
Each row will have:
6*12/8 = 9 tiles
The total area covered by one row of tiles is:
9*8*8 = 576 in^2 or
576/(6*6) ft^2 = 16 ft^2 (since 1 ft^2 = 6*6 in^2)