Problema Solution
Romeo bought a mixture of 27, $.35, and 50 Cent valentines. The number of 27 valentines was one more than twice the number of $.35 Valentines, and the number of 50 Cent valentines with two less than the number of $.35 ones. If he spent $4.20 altogether, how many valentines of each kind did you buy?
Answer provided by our tutors
Let
x = the number of 35 cent valentines
1 + 2x = the number of 27 cent valentines
x - 2 = the number of 50 cent valentines
35x + 27(1 + 2x) + 50(x - 2) = 420
........
click here to see the equation solved for x
........
x = 3.55
1 + 2x = 8.1
3.55 - 2 = 1.55
Romeo bough 3.55 valentines of 35 cents, 8.1 valentines of 27 cents and 1.55 valentines of 50 cents.