Problema Solution
A triangle has a perimeter of 53 in. The shortest side of the triangle is two more than one-third of the longest side. The other side is five less than the longest side. Find the dimensions.
Answer provided by our tutors
perimeter = 53
longest side: x
shortest side: x/3 + 2
middle side: x - 5
x + x - 5 + x/3 + 2 = 53
7x/3 = 56
x = 24.
So, the sides are: 24, 19 and 10.