Problema Solution
You need a 40% alcohol solution. On hand, you have a 600 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution? mL of pure water
to obtain mL of the desired 40% solution.
Answer provided by our tutors
For simplicity. We have 600 mL of 85% alcohol mixture = 510 mL of alcohol. 510 / 40% = amount of total liquid we need to have = 1,274. We already have 600 mL of liquid so 1,274 mL - 600 mL = 674 mL of pure water needed to get the desired solution.