Problema Solution
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 20% antifreeze to get a mixture that is 50% antifreeze?
Answer provided by our tutors
G total gallons of 50% mixture is desired
where G = 80 + x
0.6*80 = #gallons of antifreeze in the 60% mixture
(0.6*80 + 0.2*x)/(80+x)=0.5
48+0.2x=40+.5x
.3x=8
x=8/.3=26.667
so add just under 27 gallons of 20% antifreeze