Problema Solution
The combined area of a square and rectangle is 44 square centimeters and the width of a rectangle is 3 centimeters more than the length of a side of the square. The length of the rectangle is 3 centimeters more than its width. Find the ddimensions of the square and rectangle.
Answer provided by our tutors
A+B=44sq. mt.
Let l,w be the dimensions of rectangel.
l=w+3.
Let "S" be the side of square.
(3+s)(s+3+3)+s^2=44.
(3+s)(s+6)=44.
3s+18+s^2+6s=44.
s^2+9s+18-44=0.
s^2+9s-26=0.
(s+13)(s-2)=0.
s=2 cm.
w=s+3=2+3=5 cm.
lk=w+3=5+3=8 cm