Problema Solution
Sarah has a collection of nickels, dimes, and quarters worth $14.45. She has 10 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?
Answer provided by our tutors
5n + 10d + 25q = 1445
d = n + 10
q = 2d
n = d - 10
So...
5(d - 10) + 10d + 25(2d) = 1445
5d - 50 + 10d +50d = 1445
65d -50 = 1445
65d = 1495
d = 23
Therefore, she has 13 nickels, 23 dimes, and 46 quarters.