Problema Solution
What quantity of pure acid must be added to 600mL of a 45% acid solution to produce a 70% acid solution
Answer provided by our tutors
x + .45(600) = .70(600+x)
x + 270 = 420+.70x
.30x + 270 = 420
.30x = 150
x = 500 mL
What quantity of pure acid must be added to 600mL of a 45% acid solution to produce a 70% acid solution
x + .45(600) = .70(600+x)
x + 270 = 420+.70x
.30x + 270 = 420
.30x = 150
x = 500 mL