Problema Solution
How many mg of metal containing 45% nickel must be combined with 6mg of pure nickel to form an alloy containing 78% nickel
Answer provided by our tutors
solve for x
45% x + 6 = 78% (x+6)
--Let x represent pure nickel, then 78%(x + 6mg) = 45%x + 6mg
Multiplying both sides by 100 to remove percentages, 78(x + 6mg) = 45x + 600mg
Simplifying left hand side, 78x + 468 = 45x + 600mg
Transposing like terms, 78x - 45x = 600mg - 468mg
Subtracting like terms, 33x = 132
Dividing both sides by 33, x = 4mg
Answer: 4mg 45% nickel must be combined with 6mg pure nickel to form a 78% nickel alloy.