Problema Solution
the length of one leg of a right triangle is 9 feet. the length of the hypotenuse is 3 feet longer than the other leg. find the length of the hypotenuse and the other leg
Answer provided by our tutors
a^2 + b^2 = c^2
Since the hypotenuse (c) is 3 feet longer then the other leg (b) we can write the equation like this
9^2 +b^2 = (b+3)^2
81+b^2=b^2+6b+9
If you subtract b^2 from both sides they cancel each other out. You can also subtract 9 from both sides which will give you
72 = 6b
You divide both sides by 6 to give you b = 12
now you can solve for c in the original equation
9^2 +12^2 = c^2
81 + 144 = c^2
255 = c^2
take the square root of both sides
c = 15
So the other leg is 12 feet long and the hypotenuse is 15 feet long.