Problema Solution
a private plane traveled from Seattle to a rugged wilderness, at an average speed of 108mph. On the return trip, the average speed was 135 mph. If the total traveling time was 5 hour, how far is Seattle from the wilderness?
Answer provided by our tutors
we have two equn here,
let t1 = forwrd time and t2 = backward time
==> 108t1 = 135t2
and t1 + t2 = 5
==> 108(5-t2) = 135t2
==> 108*5 = 135t2 + 108t2
==> t2 = 540/243 = 60/27=20/9 hrs.
Hence, distance = 135* 20/9 = 15*20 = 300 miles