Problema Solution
The radiator in my car contains 6.3 L and water. This mixture is 30% antifreeze. How much of this mixture should she drain and replace with pure antifreeze, so that there will be a mixture of 50% antifreeze?
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Answer...
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percent ---------------- quantity
Antifreez1 I 80 ---------------- 40 gallons
Antifreeze II 10 ---------------- x gallons
Total 30 ---------------- 40 + x gallons
=30*6.3+100*x=50(6.3+x)
=189+100x =315+50x
=100x-50x =315-189
=50x=126
/50
x=2.52 liters 100% Antifreeze