Problema Solution
a rectangular piece of metal is 30 in longer than it is wide. Squares with sides 6 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 3024 in^3, what were the original dimensions of the piece of metal? What is the original width in inches?
Answer provided by our tutors
let x be the width so length =x+30
if we cut 6 inches squared the the box will have length = x+30-12 =x+18
width =x-12
height =6
give volume =3024 =(x-12)(x+18)(6)
or 504 =x2-6x-216
x2-6x-720=0
x =6+54/2 =30 icnhes