Problema Solution
Two consecutive integers are such that one quarterof the first added to one seventh of the second is greater than 19.determine the smallest possible values for the numbers.
Answer provided by our tutors
x/4 + (x+1)/7 > 19
Multiply two sides with 28
-> 7x + 4(x+1) > 532
=> 7x+4x + 4 > 532
=> 11x> 528
-> x > 48