Problema Solution
Find the second of three consecutive integers if the sum of twice the first and 4 times the second is equal to 20 more than twice the third.
Answer provided by our tutors
let the integer be x
second=x+1
third=x+2
=> 2x+4(x+1) = 20+2(x+2)
=> 6x + 4 = 2x + 24
=> 4x = 20
=>x=5
second integer = 6