Problema Solution
four times the sum of the first and third of three consecutive integers is 140 more than the second integer. find the integers
Answer provided by our tutors
Acc to the given equation
let the three consecutive integers be ( x , x+1, x+2)
4 ( x+x+2) = 140+x+1
hence
4(2x+2) = 141+x
8x+8 -x =141
7x = 133 x = 19
Hence the integers are 19,20,21