Problema Solution
In singles competition, each player plays on a rectangular area of 117 square yards. Given that the length of that area is 4 yards greater than its width, find the length and width.
Answer provided by our tutors
given area = 117 = lenght * width
given lenght = width + 4
Hence putting in ist equ we get
117 = length * width = width (width +4)
width^2 +4width -117 = 0
width= w
w^2 +13w-9w-117 = 0
w(w+13) -9(w+13)=0
(w-9) (w+13)=0
Ignoring negative value w = 9
hence lenght = 9+4 = 13