A toy rocket is launched at an initial velocity of 14.7 m/s from a platform that sits 49 meters

above the ground. The height h of the rocket above the ground at any time t seconds after

launch is given by the equation h  4.9t2 14.7t  49 . When will the rocket hit the ground?

Solution:

             h = 14.7t - 4.9t^2

             0 = t(14.7 - 4.9t)

                 t = 3 sec