Problema Solution
Starting st the same point in a forest, two hikers take different paths. The first hiker walks due north at a speed of 3 miles per hour. The second hiker walks 60 degrees west of north at a speed of 4 miles per hour. How far apart are the hikers after 1 hour? The two hikers carry walkie-talkies with a range of 8 miles. After how much time are the hikers out of range of each other? Suppose after two hours the frst hiker stops and tells the second hiker to meet her. How long will it take the second hiker to met the first hiker? In what direction should the second hiker walk?
Answer provided by our tutors
First state the known
Hiker one travels at 3 mi/hr north and hiker 2 travels 4mi/hr 60 degrees west of north.
To find the total distance between the two hikers after 1 hour break the hiker 2 velocity into it's x and y components.
Hiker two x componet= 4cos30 degrees=3.464mi/hr
Hiker two y componet=4sin30 degrees=2mi/hr
Add and use pathagorean's theorem
total x=3.464mi
total y=5mi
Total distance=sqrt(37)
=6.08mi apart
Hope this helps :D