find two consecutive odd integers such that five times their sum is 23 less than their product

let one integer = x

other integer = x+2

according to question:

(x+x+2)*5 = x(x+2) - 23

=> x^2 + 2x -23 = 10x + 10

=> x^2 - 8x - 33=0

=> (x-11)(x+3) = 0

x = 11

x = -3

consecutive integers: 11, 13

OR  -3,-1