Problema Solution
A twin engine aircraft can fly 612 miles from city A to city B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind?
Answer provided by our tutors
let speed of aircraft be x and of wind be ymph
3(x+y) = 612
x+y = 204
6(x-y ) = 612
x-y = 102
on solving y = 51 mph9