y1=x^2 +1

x+2y=5 => y2= (5-x)/2

consider y1=y2

x^2+1 = (5-x)/2

2x^2+2 = 5-x

2x^2 +x -3=0

2x^2-2x +3x -3=0

(2x^2 -2x) + (3x-3)=0

2x(x-1)+3(x-1)=0

(x-1)(2x+3)=0

=> x = 1 and x= -3/2

y= (5-1)/2=2  point (1,2)

y=(5-(-3/2))/2= 13/4, point (-3/2; 13/4)