One number exceeds three times a second number by 7. The sum of twice the larger number and four times the smaller number is 44. Write a system of equations for the given data with x being the larger number and y being the smaller number and find the two numbers

Solution:

First number: 3x+7

Second number: x

2(3x+7)+4x =44

10x=30

x=3

so

First number: 16

Second number: 3