Y varies directly as x and inversely as the square of z. y=34 when x=50 and z=5. Find y when x=45 and z=3.

y=__

Solution:

y =kx/z^2

34 = 50k/25

k=17

So

y = 17x/z^2 = 17*45/3^2 = 85

So

y=85 when x=45 and z=3